Base | Representation |
---|---|
bin | 100000000101110010100111… |
… | …110110011100010000001110 |
3 | 200111201102020120120122020211 |
4 | 200011302213312130100032 |
5 | 121444330341000210014 |
6 | 1220100420545033034 |
7 | 41504461544043520 |
oct | 4005624766342016 |
9 | 614642216518224 |
10 | 141135441413134 |
11 | 40a74228314513 |
12 | 139b4bb192577a |
13 | 609a026cc0a3c |
14 | 26bcdc5765a10 |
15 | 114b3cb661cc4 |
hex | 805ca7d9c40e |
141135441413134 has 16 divisors (see below), whose sum is σ = 243298127260800. Its totient is φ = 60148703681784.
The previous prime is 141135441413129. The next prime is 141135441413191. The reversal of 141135441413134 is 431314144531141.
141135441413134 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28159502964 + ... + 28159507975.
It is an arithmetic number, because the mean of its divisors is an integer number (15206132953800).
Almost surely, 2141135441413134 is an apocalyptic number.
141135441413134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
141135441413134 is a deficient number, since it is larger than the sum of its proper divisors (102162685847666).
141135441413134 is a wasteful number, since it uses less digits than its factorization.
141135441413134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56319011127.
The product of its digits is 138240, while the sum is 40.
Adding to 141135441413134 its reverse (431314144531141), we get a palindrome (572449585944275).
The spelling of 141135441413134 in words is "one hundred forty-one trillion, one hundred thirty-five billion, four hundred forty-one million, four hundred thirteen thousand, one hundred thirty-four".
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