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141140134242539 is a prime number
BaseRepresentation
bin100000000101110110111111…
…100100001010100011101011
3200111201212100121222001222022
4200011312333210022203223
5121444414443331230124
61220102514344415055
741505016046325065
oct4005667744124353
9614655317861868
10141140134242539
1140a7621629a723
12139b5aa147748b
13609a5c4310a83
1426bd30cb08735
15114b5a363ec5e
hex805dbf90a8eb

141140134242539 has 2 divisors, whose sum is σ = 141140134242540. Its totient is φ = 141140134242538.

The previous prime is 141140134242343. The next prime is 141140134242557. The reversal of 141140134242539 is 935242431041141.

141140134242539 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (935242431041141) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141140134242539 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 141140134242539.

It is not a weakly prime, because it can be changed into another prime (141140134742539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70570067121269 + 70570067121270.

It is an arithmetic number, because the mean of its divisors is an integer number (70570067121270).

Almost surely, 2141140134242539 is an apocalyptic number.

141140134242539 is a deficient number, since it is larger than the sum of its proper divisors (1).

141140134242539 is an equidigital number, since it uses as much as digits as its factorization.

141140134242539 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 414720, while the sum is 44.

The spelling of 141140134242539 in words is "one hundred forty-one trillion, one hundred forty billion, one hundred thirty-four million, two hundred forty-two thousand, five hundred thirty-nine".