141142433010111 has 64 divisors (see below), whose sum is σ = 227356268912640. Its totient is φ = 86019683114880.

The previous prime is 141142433010101. The next prime is 141142433010127. The reversal of 141142433010111 is 111010334241141.

141142433010111 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 4 + 243 + 301 + 0 + 111 = 666.

It is not a de Polignac number, because 141142433010111 - 2²⁶ = 141142365901247 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141142433010101) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 126801661 + ... + 127909913.

It is an arithmetic number, because the mean of its divisors is an integer number (3552441701760).

Almost surely, 2^{141142433010111} is an apocalyptic number.

141142433010111 is a deficient number, since it is larger than the sum of its proper divisors (86213835902529).

141142433010111 is a wasteful number, since it uses less digits than its factorization.

141142433010111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1111773 (or 1111767 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 27.

Adding to 141142433010111 its reverse (111010334241141), we get a palindrome (252152767251252).

The spelling of 141142433010111 in words is "one hundred forty-one trillion, one hundred forty-two billion, four hundred thirty-three million, ten thousand, one hundred eleven".