Base | Representation |
---|---|
bin | 1100110101100011111100… |
… | …1011001111111101001001 |
3 | 1211222022112101210001100201 |
4 | 3031120333023033331021 |
5 | 3322222113021320301 |
6 | 50004010305532201 |
7 | 2654504032210603 |
oct | 315307713177511 |
9 | 54868471701321 |
10 | 14114322448201 |
11 | 455193a076038 |
12 | 16bb54a044061 |
13 | 7b4c89accbc1 |
14 | 36b1cb740173 |
15 | 19722c711201 |
hex | cd63f2cff49 |
14114322448201 has 2 divisors, whose sum is σ = 14114322448202. Its totient is φ = 14114322448200.
The previous prime is 14114322448157. The next prime is 14114322448207. The reversal of 14114322448201 is 10284422341141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12907672925625 + 1206649522576 = 3592725^2 + 1098476^2 .
It is a cyclic number.
It is not a de Polignac number, because 14114322448201 - 225 = 14114288893769 is a prime.
It is not a weakly prime, because it can be changed into another prime (14114322448207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7057161224100 + 7057161224101.
It is an arithmetic number, because the mean of its divisors is an integer number (7057161224101).
Almost surely, 214114322448201 is an apocalyptic number.
It is an amenable number.
14114322448201 is a deficient number, since it is larger than the sum of its proper divisors (1).
14114322448201 is an equidigital number, since it uses as much as digits as its factorization.
14114322448201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 49152, while the sum is 37.
Adding to 14114322448201 its reverse (10284422341141), we get a palindrome (24398744789342).
The spelling of 14114322448201 in words is "fourteen trillion, one hundred fourteen billion, three hundred twenty-two million, four hundred forty-eight thousand, two hundred one".
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