Base | Representation |
---|---|
bin | 10100100010100000101… |
… | …001011111001110111001 |
3 | 11222221011222211210212011 |
4 | 110202200221133032321 |
5 | 141111114243102411 |
6 | 3000224134045521 |
7 | 203654624220265 |
oct | 24424051371671 |
9 | 4887158753764 |
10 | 1411444503481 |
11 | 4a4654698131 |
12 | 1a9669aa98a1 |
13 | a313895541c |
14 | 4c4585470a5 |
15 | 26aacc53c21 |
hex | 148a0a5f3b9 |
1411444503481 has 2 divisors, whose sum is σ = 1411444503482. Its totient is φ = 1411444503480.
The previous prime is 1411444503439. The next prime is 1411444503487. The reversal of 1411444503481 is 1843054441141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1390713111225 + 20731392256 = 1179285^2 + 143984^2 .
It is a cyclic number.
It is not a de Polignac number, because 1411444503481 - 215 = 1411444470713 is a prime.
It is a super-2 number, since 2×14114445034812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1411444503487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705722251740 + 705722251741.
It is an arithmetic number, because the mean of its divisors is an integer number (705722251741).
Almost surely, 21411444503481 is an apocalyptic number.
It is an amenable number.
1411444503481 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411444503481 is an equidigital number, since it uses as much as digits as its factorization.
1411444503481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122880, while the sum is 40.
The spelling of 1411444503481 in words is "one trillion, four hundred eleven billion, four hundred forty-four million, five hundred three thousand, four hundred eighty-one".
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