Base | Representation |
---|---|
bin | 1100110101100110111101… |
… | …0011111110101110101001 |
3 | 1211222101121200102010120111 |
4 | 3031121233103332232221 |
5 | 3322230241242341210 |
6 | 50004222355254321 |
7 | 2654533036516354 |
oct | 315315723765651 |
9 | 54871550363514 |
10 | 14115130043305 |
11 | 4552213a24205 |
12 | 16bb7345aa3a1 |
13 | 7b5088211b25 |
14 | 36b266ac529b |
15 | 19727858888a |
hex | cd66f4feba9 |
14115130043305 has 32 divisors (see below), whose sum is σ = 17472618252288. Its totient is φ = 10940666496000.
The previous prime is 14115130043303. The next prime is 14115130043309. The reversal of 14115130043305 is 50334003151141.
It is not a de Polignac number, because 14115130043305 - 21 = 14115130043303 is a prime.
It is a super-2 number, since 2×141151300433052 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14115130043303) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 159051345 + ... + 159140065.
It is an arithmetic number, because the mean of its divisors is an integer number (546019320384).
Almost surely, 214115130043305 is an apocalyptic number.
It is an amenable number.
14115130043305 is a deficient number, since it is larger than the sum of its proper divisors (3357488208983).
14115130043305 is a wasteful number, since it uses less digits than its factorization.
14115130043305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95577.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 14115130043305 its reverse (50334003151141), we get a palindrome (64449133194446).
The spelling of 14115130043305 in words is "fourteen trillion, one hundred fifteen billion, one hundred thirty million, forty-three thousand, three hundred five".
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