1411535341141 has 4 divisors (see below), whose sum is σ = 1417027696812. Its totient is φ = 1406042985472.

The previous prime is 1411535341133. The next prime is 1411535341159. The reversal of 1411535341141 is 1411435351141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 930156086916 + 481379254225 = 964446^2 + 693815^2 .

It is a cyclic number.

It is not a de Polignac number, because 1411535341141 - 2³ = 1411535341133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1411535341097 and 1411535341106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411535341841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2746177450 + ... + 2746177963.

It is an arithmetic number, because the mean of its divisors is an integer number (354256924203).

Almost surely, 2^{1411535341141} is an apocalyptic number.

It is an amenable number.

1411535341141 is a deficient number, since it is larger than the sum of its proper divisors (5492355671).

1411535341141 is an equidigital number, since it uses as much as digits as its factorization.

1411535341141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5492355670.

The product of its digits is 14400, while the sum is 34.

The spelling of 1411535341141 in words is "one trillion, four hundred eleven billion, five hundred thirty-five million, three hundred forty-one thousand, one hundred forty-one".