Base | Representation |
---|---|
bin | 100000000110000100001101… |
… | …001011111000000110110011 |
3 | 200111210012222100121100122122 |
4 | 200012010031023320012303 |
5 | 122000133022234301433 |
6 | 1220113222224424455 |
7 | 41506030446222644 |
oct | 4006041513700663 |
9 | 614705870540578 |
10 | 141154321400243 |
11 | 40a812365aa248 |
12 | 139b87a077812b |
13 | 609ba4562b748 |
14 | 26bdc96dbd6cb |
15 | 114bb33de2198 |
hex | 80610d2f81b3 |
141154321400243 has 2 divisors, whose sum is σ = 141154321400244. Its totient is φ = 141154321400242.
The previous prime is 141154321400237. The next prime is 141154321400293. The reversal of 141154321400243 is 342004123451141.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141154321400243 is a prime.
It is not a weakly prime, because it can be changed into another prime (141154321400293) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70577160700121 + 70577160700122.
It is an arithmetic number, because the mean of its divisors is an integer number (70577160700122).
Almost surely, 2141154321400243 is an apocalyptic number.
141154321400243 is a deficient number, since it is larger than the sum of its proper divisors (1).
141154321400243 is an equidigital number, since it uses as much as digits as its factorization.
141154321400243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 141154321400243 its reverse (342004123451141), we get a palindrome (483158444851384).
The spelling of 141154321400243 in words is "one hundred forty-one trillion, one hundred fifty-four billion, three hundred twenty-one million, four hundred thousand, two hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •