141154812491993 has 2 divisors, whose sum is σ = 141154812491994. Its totient is φ = 141154812491992.

The previous prime is 141154812491939. The next prime is 141154812492007. The reversal of 141154812491993 is 399194218451141.

Together with previous prime (141154812491939) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101738854018624 + 39415958473369 = 10086568^2 + 6278213^2 .

It is a cyclic number.

It is not a de Polignac number, because 141154812491993 - 2¹⁰ = 141154812490969 is a prime.

It is a super-2 number, since 2×141154812491993² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (141154812491093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70577406245996 + 70577406245997.

It is an arithmetic number, because the mean of its divisors is an integer number (70577406245997).

Almost surely, 2^{141154812491993} is an apocalyptic number.

It is an amenable number.

141154812491993 is a deficient number, since it is larger than the sum of its proper divisors (1).

141154812491993 is an equidigital number, since it uses as much as digits as its factorization.

141154812491993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11197440, while the sum is 62.

The spelling of 141154812491993 in words is "one hundred forty-one trillion, one hundred fifty-four billion, eight hundred twelve million, four hundred ninety-one thousand, nine hundred ninety-three".