Base | Representation |
---|---|
bin | 11010010011001111… |
… | …01001110101110011 |
3 | 1100110001100000210022 |
4 | 31021213221311303 |
5 | 212404212034101 |
6 | 10253041154055 |
7 | 1006623206603 |
oct | 151147516563 |
9 | 40401300708 |
10 | 14120033651 |
11 | 5a964332a9 |
12 | 28a092b92b |
13 | 14404481c9 |
14 | 97d400c03 |
15 | 579943a1b |
hex | 3499e9d73 |
14120033651 has 2 divisors, whose sum is σ = 14120033652. Its totient is φ = 14120033650.
The previous prime is 14120033611. The next prime is 14120033659. The reversal of 14120033651 is 15633002141.
It is a strong prime.
It is an emirp because it is prime and its reverse (15633002141) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14120033651 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14120033651.
It is not a weakly prime, because it can be changed into another prime (14120033659) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060016825 + 7060016826.
It is an arithmetic number, because the mean of its divisors is an integer number (7060016826).
Almost surely, 214120033651 is an apocalyptic number.
14120033651 is a deficient number, since it is larger than the sum of its proper divisors (1).
14120033651 is an equidigital number, since it uses as much as digits as its factorization.
14120033651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 14120033651 its reverse (15633002141), we get a palindrome (29753035792).
The spelling of 14120033651 in words is "fourteen billion, one hundred twenty million, thirty-three thousand, six hundred fifty-one".
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