14120113 has 8 divisors (see below), whose sum is σ = 16531200. Its totient is φ = 11807520.

The previous prime is 14120089. The next prime is 14120123. The reversal of 14120113 is 31102141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14120113 is a prime.

It is a super-2 number, since 2×14120113² = 398755182265538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14120093 and 14120102.

It is not an unprimeable number, because it can be changed into a prime (14120123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24313 + ... + 24886.

It is an arithmetic number, because the mean of its divisors is an integer number (2066400).

Almost surely, 2^14120113 is an apocalyptic number.

It is an amenable number.

14120113 is a deficient number, since it is larger than the sum of its proper divisors (2411087).

14120113 is an equidigital number, since it uses as much as digits as its factorization.

14120113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49247.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 14120113 is about 3757.6738815390. The cubic root of 14120113 is about 241.7015251078.

Adding to 14120113 its reverse (31102141), we get a palindrome (45222254).

The spelling of 14120113 in words is "fourteen million, one hundred twenty thousand, one hundred thirteen".