14120123 has 2 divisors, whose sum is σ = 14120124. Its totient is φ = 14120122.

The previous prime is 14120089. The next prime is 14120143. The reversal of 14120123 is 32102141.

It is a strong prime.

It is an emirp because it is prime and its reverse (32102141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14120123 - 2¹⁰ = 14119099 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14120098 and 14120107.

It is not a weakly prime, because it can be changed into another prime (14120143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060061 + 7060062.

It is an arithmetic number, because the mean of its divisors is an integer number (7060062).

Almost surely, 2^14120123 is an apocalyptic number.

14120123 is a deficient number, since it is larger than the sum of its proper divisors (1).

14120123 is an equidigital number, since it uses as much as digits as its factorization.

14120123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 14120123 is about 3757.6752121491. The cubic root of 14120123 is about 241.7015821662.

Adding to 14120123 its reverse (32102141), we get a palindrome (46222264).

The spelling of 14120123 in words is "fourteen million, one hundred twenty thousand, one hundred twenty-three".