141201303113137 has 2 divisors, whose sum is σ = 141201303113138. Its totient is φ = 141201303113136.

The previous prime is 141201303113089. The next prime is 141201303113141. The reversal of 141201303113137 is 731311303102141.

141201303113137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108335435881761 + 32865867231376 = 10408431^2 + 5732876^2 .

It is a cyclic number.

It is not a de Polignac number, because 141201303113137 - 2¹⁹ = 141201302588849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141201303113099 and 141201303113108.

It is not a weakly prime, because it can be changed into another prime (141201303113737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600651556568 + 70600651556569.

It is an arithmetic number, because the mean of its divisors is an integer number (70600651556569).

Almost surely, 2^{141201303113137} is an apocalyptic number.

It is an amenable number.

141201303113137 is a deficient number, since it is larger than the sum of its proper divisors (1).

141201303113137 is an equidigital number, since it uses as much as digits as its factorization.

141201303113137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4536, while the sum is 31.

Adding to 141201303113137 its reverse (731311303102141), we get a palindrome (872512606215278).

The spelling of 141201303113137 in words is "one hundred forty-one trillion, two hundred one billion, three hundred three million, one hundred thirteen thousand, one hundred thirty-seven".