Base | Representation |
---|---|
bin | 100000000110101111111101… |
… | …100000111000111001011111 |
3 | 200111221201020120222122222121 |
4 | 200012233331200320321133 |
5 | 122001420232044111221 |
6 | 1220150552205523411 |
7 | 41512312631210230 |
oct | 4006577540707137 |
9 | 614851216878877 |
10 | 141201303113311 |
11 | 40a9a155551691 |
12 | 13a05912873567 |
13 | 60a32c1c8346c |
14 | 26c2272907087 |
15 | 114ce837cea41 |
hex | 806bfd838e5f |
141201303113311 has 8 divisors (see below), whose sum is σ = 161617793293440. Its totient is φ = 120846031795608.
The previous prime is 141201303113287. The next prime is 141201303113333. The reversal of 141201303113311 is 113311303102141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 141201303113311 - 221 = 141201301016159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141201303113911) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15304710661 + ... + 15304719886.
It is an arithmetic number, because the mean of its divisors is an integer number (20202224161680).
Almost surely, 2141201303113311 is an apocalyptic number.
141201303113311 is a deficient number, since it is larger than the sum of its proper divisors (20416490180129).
141201303113311 is an equidigital number, since it uses as much as digits as its factorization.
141201303113311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30609431213.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 141201303113311 its reverse (113311303102141), we get a palindrome (254512606215452).
The spelling of 141201303113311 in words is "one hundred forty-one trillion, two hundred one billion, three hundred three million, one hundred thirteen thousand, three hundred eleven".
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