Base | Representation |
---|---|
bin | 10100100011000010100… |
… | …010111011111010101111 |
3 | 11222222122121222011100010 |
4 | 110203002202323322233 |
5 | 141113300340230221 |
6 | 3000400411304303 |
7 | 204005001156513 |
oct | 24430242737257 |
9 | 4888577864303 |
10 | 1412013211311 |
11 | 4a49167127aa |
12 | 1a97a844b093 |
13 | a31c9715b31 |
14 | 4c4adca6143 |
15 | 26ae2b3ec76 |
hex | 148c28bbeaf |
1412013211311 has 4 divisors (see below), whose sum is σ = 1882684281752. Its totient is φ = 941342140872.
The previous prime is 1412013211229. The next prime is 1412013211313. The reversal of 1412013211311 is 1131123102141.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1412013211311 - 27 = 1412013211183 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1412013211313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235335535216 + ... + 235335535221.
It is an arithmetic number, because the mean of its divisors is an integer number (470671070438).
Almost surely, 21412013211311 is an apocalyptic number.
1412013211311 is a deficient number, since it is larger than the sum of its proper divisors (470671070441).
1412013211311 is an equidigital number, since it uses as much as digits as its factorization.
1412013211311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 470671070440.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 1412013211311 its reverse (1131123102141), we get a palindrome (2543136313452).
The spelling of 1412013211311 in words is "one trillion, four hundred twelve billion, thirteen million, two hundred eleven thousand, three hundred eleven".
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