Base | Representation |
---|---|
bin | 100000000110110000000101… |
… | …111010110101100010110010 |
3 | 200111221201121102100012200121 |
4 | 200012300011322311202302 |
5 | 122001421024144224132 |
6 | 1220151014204240454 |
7 | 41512316262645406 |
oct | 4006600572654262 |
9 | 614851542305617 |
10 | 141201444133042 |
11 | 40a9a21810a917 |
12 | 13a05951b4012a |
13 | 60a33152599a7 |
14 | 26c2287535106 |
15 | 114ce90d88497 |
hex | 806c05eb58b2 |
141201444133042 has 4 divisors (see below), whose sum is σ = 211802166199566. Its totient is φ = 70600722066520.
The previous prime is 141201444133039. The next prime is 141201444133063. The reversal of 141201444133042 is 240331444102141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 81746534221641 + 59454909911401 = 9041379^2 + 7710701^2 .
It is a junction number, because it is equal to n+sod(n) for n = 141201444132989 and 141201444133007.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35300361033259 + ... + 35300361033262.
Almost surely, 2141201444133042 is an apocalyptic number.
141201444133042 is a deficient number, since it is larger than the sum of its proper divisors (70600722066524).
141201444133042 is an equidigital number, since it uses as much as digits as its factorization.
141201444133042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70600722066523.
The product of its (nonzero) digits is 36864, while the sum is 34.
Adding to 141201444133042 its reverse (240331444102141), we get a palindrome (381532888235183).
The spelling of 141201444133042 in words is "one hundred forty-one trillion, two hundred one billion, four hundred forty-four million, one hundred thirty-three thousand, forty-two".
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