Base | Representation |
---|---|
bin | 11010010011010000… |
… | …00110100100001000 |
3 | 1100110001120000011211 |
4 | 31021220012210020 |
5 | 212404224320204 |
6 | 10253043502504 |
7 | 1006624206610 |
oct | 151150064410 |
9 | 40401500154 |
10 | 14120151304 |
11 | 5a96503736 |
12 | 28a0987a34 |
13 | 144048991c |
14 | 97d431a40 |
15 | 579968804 |
hex | 349a06908 |
14120151304 has 32 divisors (see below), whose sum is σ = 30286713600. Its totient is φ = 6045644160.
The previous prime is 14120151293. The next prime is 14120151319. The reversal of 14120151304 is 40315102141.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63157 + ... + 179524.
It is an arithmetic number, because the mean of its divisors is an integer number (946459800).
Almost surely, 214120151304 is an apocalyptic number.
14120151304 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
14120151304 is an abundant number, since it is smaller than the sum of its proper divisors (16166562296).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14120151304 is a wasteful number, since it uses less digits than its factorization.
14120151304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 243733 (or 243729 counting only the distinct ones).
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 14120151304 its reverse (40315102141), we get a palindrome (54435253445).
The spelling of 14120151304 in words is "fourteen billion, one hundred twenty million, one hundred fifty-one thousand, three hundred four".
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