141202011131341 has 4 divisors (see below), whose sum is σ = 141202174920352. Its totient is φ = 141201847342332.

The previous prime is 141202011131303. The next prime is 141202011131449. The reversal of 141202011131341 is 143131110202141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141202011131341 - 2¹³ = 141202011123149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141202011131641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80594481 + ... + 82327846.

It is an arithmetic number, because the mean of its divisors is an integer number (35300543730088).

Almost surely, 2^{141202011131341} is an apocalyptic number.

It is an amenable number.

141202011131341 is a deficient number, since it is larger than the sum of its proper divisors (163789011).

141202011131341 is an equidigital number, since it uses as much as digits as its factorization.

141202011131341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163789010.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 141202011131341 its reverse (143131110202141), we get a palindrome (284333121333482).

The spelling of 141202011131341 in words is "one hundred forty-one trillion, two hundred two billion, eleven million, one hundred thirty-one thousand, three hundred forty-one".