Base | Representation |
---|---|
bin | 1100110101111001110110… |
… | …1100001100101110011011 |
3 | 1211222212201020021200121120 |
4 | 3031132131230030232123 |
5 | 3322321133444030243 |
6 | 50010422020540323 |
7 | 2655102540056211 |
oct | 315363554145633 |
9 | 54885636250546 |
10 | 14120203111323 |
11 | 45543875a8301 |
12 | 170070b5516a3 |
13 | 7b56b624481a |
14 | 36b5c8766cb1 |
15 | 197473b24c83 |
hex | cd79db0cb9b |
14120203111323 has 32 divisors (see below), whose sum is σ = 20232826536960. Its totient is φ = 8727114908160.
The previous prime is 14120203111319. The next prime is 14120203111363. The reversal of 14120203111323 is 32311130202141.
It is not a de Polignac number, because 14120203111323 - 22 = 14120203111319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14120203111293 and 14120203111302.
It is not an unprimeable number, because it can be changed into a prime (14120203111303) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 90400713 + ... + 90556773.
It is an arithmetic number, because the mean of its divisors is an integer number (632275829280).
Almost surely, 214120203111323 is an apocalyptic number.
14120203111323 is a deficient number, since it is larger than the sum of its proper divisors (6112623425637).
14120203111323 is a wasteful number, since it uses less digits than its factorization.
14120203111323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 182627.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 14120203111323 its reverse (32311130202141), we get a palindrome (46431333313464).
The spelling of 14120203111323 in words is "fourteen trillion, one hundred twenty billion, two hundred three million, one hundred eleven thousand, three hundred twenty-three".
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