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1412021404331 is a prime number
BaseRepresentation
bin10100100011000011000…
…010001100001010101011
311222222200012101102001022
4110203003002030022223
5141113304434414311
63000401303043055
7204005130622046
oct24430302141253
94888605342038
101412021404331
114a49202a929a
121a97ab14048b
13a31cb324085
144c4b0dd9c5d
1526ae370c5db
hex148c308c2ab

1412021404331 has 2 divisors, whose sum is σ = 1412021404332. Its totient is φ = 1412021404330.

The previous prime is 1412021404289. The next prime is 1412021404349. The reversal of 1412021404331 is 1334041202141.

It is a strong prime.

It is an emirp because it is prime and its reverse (1334041202141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1412021404331 - 218 = 1412021142187 is a prime.

It is a super-2 number, since 2×14120214043312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1412021404331.

It is not a weakly prime, because it can be changed into another prime (1412021404231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706010702165 + 706010702166.

It is an arithmetic number, because the mean of its divisors is an integer number (706010702166).

Almost surely, 21412021404331 is an apocalyptic number.

1412021404331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412021404331 is an equidigital number, since it uses as much as digits as its factorization.

1412021404331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 1412021404331 its reverse (1334041202141), we get a palindrome (2746062606472).

The spelling of 1412021404331 in words is "one trillion, four hundred twelve billion, twenty-one million, four hundred four thousand, three hundred thirty-one".