Base | Representation |
---|---|
bin | 1100110101111001111011… |
… | …1000111010000110100100 |
3 | 1211222212202122010022201021 |
4 | 3031132132320322012210 |
5 | 3322321204121021012 |
6 | 50010424015540524 |
7 | 2655103203020401 |
oct | 315363670720644 |
9 | 54885678108637 |
10 | 14120223220132 |
11 | 4554397992357 |
12 | 170071622a744 |
13 | 7b56ba465623 |
14 | 36b5cb2bd2a8 |
15 | 197475798007 |
hex | cd79ee3a1a4 |
14120223220132 has 6 divisors (see below), whose sum is σ = 24710390635238. Its totient is φ = 7060111610064.
The previous prime is 14120223220121. The next prime is 14120223220133. The reversal of 14120223220132 is 23102232202141.
It can be written as a sum of positive squares in only one way, i.e., 14109985018276 + 10238201856 = 3756326^2 + 101184^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14120223220097 and 14120223220106.
It is not an unprimeable number, because it can be changed into a prime (14120223220133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1765027902513 + ... + 1765027902520.
Almost surely, 214120223220132 is an apocalyptic number.
It is an amenable number.
14120223220132 is a deficient number, since it is larger than the sum of its proper divisors (10590167415106).
14120223220132 is a wasteful number, since it uses less digits than its factorization.
14120223220132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3530055805037 (or 3530055805035 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14120223220132 its reverse (23102232202141), we get a palindrome (37222455422273).
The spelling of 14120223220132 in words is "fourteen trillion, one hundred twenty billion, two hundred twenty-three million, two hundred twenty thousand, one hundred thirty-two".
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