1412040433 has 2 divisors, whose sum is σ = 1412040434. Its totient is φ = 1412040432.

The previous prime is 1412040419. The next prime is 1412040437. The reversal of 1412040433 is 3340402141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1401229489 + 10810944 = 37433^2 + 3288^2 .

It is a cyclic number.

It is not a de Polignac number, because 1412040433 - 2²¹ = 1409943281 is a prime.

It is not a weakly prime, because it can be changed into another prime (1412040437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706020216 + 706020217.

It is an arithmetic number, because the mean of its divisors is an integer number (706020217).

Almost surely, 2^1412040433 is an apocalyptic number.

It is an amenable number.

1412040433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412040433 is an equidigital number, since it uses as much as digits as its factorization.

1412040433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

The square root of 1412040433 is about 37577.1264601220. The cubic root of 1412040433 is about 1121.8868155924.

Adding to 1412040433 its reverse (3340402141), we get a palindrome (4752442574).

The spelling of 1412040433 in words is "one billion, four hundred twelve million, forty thousand, four hundred thirty-three".