Base | Representation |
---|---|
bin | 10100100011000101000… |
… | …100101010110101111111 |
3 | 11222222202120202011121220 |
4 | 110203011010222311333 |
5 | 141113342213434303 |
6 | 3000404524124423 |
7 | 204006024431205 |
oct | 24430504526577 |
9 | 4888676664556 |
10 | 1412055608703 |
11 | 4a4938640573 |
12 | 1a97ba696713 |
13 | a320543b94c |
14 | 4c4b5781075 |
15 | 26ae6717053 |
hex | 148c512ad7f |
1412055608703 has 4 divisors (see below), whose sum is σ = 1882740811608. Its totient is φ = 941370405800.
The previous prime is 1412055608671. The next prime is 1412055608707. The reversal of 1412055608703 is 3078065502141.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1412055608703 - 25 = 1412055608671 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1412055608707) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235342601448 + ... + 235342601453.
It is an arithmetic number, because the mean of its divisors is an integer number (470685202902).
Almost surely, 21412055608703 is an apocalyptic number.
1412055608703 is a deficient number, since it is larger than the sum of its proper divisors (470685202905).
1412055608703 is an equidigital number, since it uses as much as digits as its factorization.
1412055608703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 470685202904.
The product of its (nonzero) digits is 201600, while the sum is 42.
The spelling of 1412055608703 in words is "one trillion, four hundred twelve billion, fifty-five million, six hundred eight thousand, seven hundred three".
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