Base | Representation |
---|---|
bin | 100000000110111000011110… |
… | …100100001010000010011011 |
3 | 200111222120211212212022112201 |
4 | 200012320132210022002123 |
5 | 122002042444033141132 |
6 | 1220155103430551031 |
7 | 41513055346521253 |
oct | 4006703644120233 |
9 | 614876755768481 |
10 | 141210447552667 |
11 | 40aa3018327289 |
12 | 13a07645208477 |
13 | 60a411b63661c |
14 | 26c289d19a963 |
15 | 114d31b4dd2e7 |
hex | 806e1e90a09b |
141210447552667 has 2 divisors, whose sum is σ = 141210447552668. Its totient is φ = 141210447552666.
The previous prime is 141210447552661. The next prime is 141210447552679. The reversal of 141210447552667 is 766255744012141.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141210447552667 is a prime.
It is not a weakly prime, because it can be changed into another prime (141210447552661) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70605223776333 + 70605223776334.
It is an arithmetic number, because the mean of its divisors is an integer number (70605223776334).
Almost surely, 2141210447552667 is an apocalyptic number.
141210447552667 is a deficient number, since it is larger than the sum of its proper divisors (1).
141210447552667 is an equidigital number, since it uses as much as digits as its factorization.
141210447552667 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11289600, while the sum is 55.
The spelling of 141210447552667 in words is "one hundred forty-one trillion, two hundred ten billion, four hundred forty-seven million, five hundred fifty-two thousand, six hundred sixty-seven".
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