Base | Representation |
---|---|
bin | 11010010011011000… |
… | …00110111110001111 |
3 | 1100110010112100211212 |
4 | 31021230012332033 |
5 | 212410011422201 |
6 | 10253122205035 |
7 | 1006636142552 |
oct | 151154067617 |
9 | 40403470755 |
10 | 14121201551 |
11 | 5a97060806 |
12 | 28a11b377b |
13 | 1440766982 |
14 | 97d626699 |
15 | 579ac4abb |
hex | 349b06f8f |
14121201551 has 4 divisors (see below), whose sum is σ = 14121450504. Its totient is φ = 14120952600.
The previous prime is 14121201547. The next prime is 14121201557. The reversal of 14121201551 is 15510212141.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14121201551 - 22 = 14121201547 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14121201557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6656 + ... + 168186.
It is an arithmetic number, because the mean of its divisors is an integer number (3530362626).
Almost surely, 214121201551 is an apocalyptic number.
14121201551 is a deficient number, since it is larger than the sum of its proper divisors (248953).
14121201551 is an equidigital number, since it uses as much as digits as its factorization.
14121201551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 248952.
The product of its (nonzero) digits is 400, while the sum is 23.
Adding to 14121201551 its reverse (15510212141), we get a palindrome (29631413692).
The spelling of 14121201551 in words is "fourteen billion, one hundred twenty-one million, two hundred one thousand, five hundred fifty-one".
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