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1412130040130 = 25141213004013
BaseRepresentation
bin10100100011001001100…
…000100110100101000010
311222222221202210200100102
4110203021200212211002
5141114020242241010
63000420143322402
7204010620202355
oct24431140464502
94888852720312
101412130040130
114a4976658a47
121a981b5b0402
13a321799c504
144c4c15d829c
1526aed01aba5
hex148c9826942

1412130040130 has 8 divisors (see below), whose sum is σ = 2541834072252. Its totient is φ = 564852016048.

The previous prime is 1412130040127. The next prime is 1412130040163. The reversal of 1412130040130 is 310400312141.

It can be written as a sum of positive squares in 2 ways, for example, as 1392024785281 + 20105254849 = 1179841^2 + 141793^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×14121300401302 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70606501997 + ... + 70606502016.

Almost surely, 21412130040130 is an apocalyptic number.

1412130040130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1412130040130 is a deficient number, since it is larger than the sum of its proper divisors (1129704032122).

1412130040130 is a wasteful number, since it uses less digits than its factorization.

1412130040130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 141213004020.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1412130040130 its reverse (310400312141), we get a palindrome (1722530352271).

The spelling of 1412130040130 in words is "one trillion, four hundred twelve billion, one hundred thirty million, forty thousand, one hundred thirty".

Divisors: 1 2 5 10 141213004013 282426008026 706065020065 1412130040130