14121325515013 has 4 divisors (see below), whose sum is σ = 14144212591020. Its totient is φ = 14098438439008.

The previous prime is 14121325515001. The next prime is 14121325515029. The reversal of 14121325515013 is 31051552312141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4847491696804 + 9273833818209 = 2201702^2 + 3045297^2 .

It is a cyclic number.

It is not a de Polignac number, because 14121325515013 - 2³³ = 14112735580421 is a prime.

It is a super-3 number, since 3×14121325515013³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14121325515013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14121325515083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11443537078 + ... + 11443538311.

It is an arithmetic number, because the mean of its divisors is an integer number (3536053147755).

Almost surely, 2^{14121325515013} is an apocalyptic number.

It is an amenable number.

14121325515013 is a deficient number, since it is larger than the sum of its proper divisors (22887076007).

14121325515013 is an equidigital number, since it uses as much as digits as its factorization.

14121325515013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22887076006.

The product of its (nonzero) digits is 18000, while the sum is 34.

Adding to 14121325515013 its reverse (31051552312141), we get a palindrome (45172877827154).

The spelling of 14121325515013 in words is "fourteen trillion, one hundred twenty-one billion, three hundred twenty-five million, five hundred fifteen thousand, thirteen".