Base | Representation |
---|---|
bin | 1000001110000011111… |
… | …0000010111111001101 |
3 | 111111111101202200001120 |
4 | 2003200332002333031 |
5 | 4303201102040041 |
6 | 144512243231153 |
7 | 13126253241612 |
oct | 2034076027715 |
9 | 444441680046 |
10 | 141213315021 |
11 | 54985264729 |
12 | 234500784b9 |
13 | 10416068b8c |
14 | 6b98826509 |
15 | 3a174dc366 |
hex | 20e0f82fcd |
141213315021 has 4 divisors (see below), whose sum is σ = 188284420032. Its totient is φ = 94142210012.
The previous prime is 141213315011. The next prime is 141213315049. The reversal of 141213315021 is 120513312141.
141213315021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 141213315021 - 215 = 141213282253 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 141213314982 and 141213315000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141213315011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23535552501 + ... + 23535552506.
It is an arithmetic number, because the mean of its divisors is an integer number (47071105008).
Almost surely, 2141213315021 is an apocalyptic number.
It is an amenable number.
141213315021 is a deficient number, since it is larger than the sum of its proper divisors (47071105011).
141213315021 is an equidigital number, since it uses as much as digits as its factorization.
141213315021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47071105010.
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 141213315021 its reverse (120513312141), we get a palindrome (261726627162).
The spelling of 141213315021 in words is "one hundred forty-one billion, two hundred thirteen million, three hundred fifteen thousand, twenty-one".
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