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141218109443737 is a prime number
BaseRepresentation
bin100000000110111111100111…
…001111111100111010011001
3200112000022121212001201012001
4200012333213033330322121
5122002204142004144422
61220202412011521001
741513446253521144
oct4006774717747231
9615008555051161
10141218109443737
1140aa629a261467
1213a09023159161
1360a4a6cac7a91
1426c2dc89b105b
15114d618e9d227
hex806fe73fce99

141218109443737 has 2 divisors, whose sum is σ = 141218109443738. Its totient is φ = 141218109443736.

The previous prime is 141218109443641. The next prime is 141218109443777. The reversal of 141218109443737 is 737344901812141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127508721984576 + 13709387459161 = 11291976^2 + 3702619^2 .

It is a cyclic number.

It is not a de Polignac number, because 141218109443737 - 215 = 141218109410969 is a prime.

It is not a weakly prime, because it can be changed into another prime (141218109443777) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70609054721868 + 70609054721869.

It is an arithmetic number, because the mean of its divisors is an integer number (70609054721869).

Almost surely, 2141218109443737 is an apocalyptic number.

It is an amenable number.

141218109443737 is a deficient number, since it is larger than the sum of its proper divisors (1).

141218109443737 is an equidigital number, since it uses as much as digits as its factorization.

141218109443737 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4064256, while the sum is 55.

The spelling of 141218109443737 in words is "one hundred forty-one trillion, two hundred eighteen billion, one hundred nine million, four hundred forty-three thousand, seven hundred thirty-seven".