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1412200252543 = 10566713364629
BaseRepresentation
bin10100100011001101101…
…100011100010001111111
312000000010122220211200011
4110203031230130101333
5141114141231040133
63000431132244051
7204012432042313
oct24431554342177
95000118824604
101412200252543
114a4a02254633
121a983b010627
13a32293b3912
144c4caa73b43
1526b042896cd
hex148cdb1c47f

1412200252543 has 4 divisors (see below), whose sum is σ = 1412213722840. Its totient is φ = 1412186782248.

The previous prime is 1412200252531. The next prime is 1412200252571. The reversal of 1412200252543 is 3452520022141.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1412200252543 - 25 = 1412200252511 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1412200252643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6576648 + ... + 6787981.

It is an arithmetic number, because the mean of its divisors is an integer number (353053430710).

Almost surely, 21412200252543 is an apocalyptic number.

1412200252543 is a deficient number, since it is larger than the sum of its proper divisors (13470297).

1412200252543 is a wasteful number, since it uses less digits than its factorization.

1412200252543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13470296.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 1412200252543 its reverse (3452520022141), we get a palindrome (4864720274684).

The spelling of 1412200252543 in words is "one trillion, four hundred twelve billion, two hundred million, two hundred fifty-two thousand, five hundred forty-three".

Divisors: 1 105667 13364629 1412200252543