Base | Representation |
---|---|
bin | 11010010011011110… |
… | …01100101011000101 |
3 | 1100110012001111122210 |
4 | 31021233030223011 |
5 | 212410213330313 |
6 | 10253151414033 |
7 | 1006646054463 |
oct | 151157145305 |
9 | 40405044583 |
10 | 14122011333 |
11 | 5a97564151 |
12 | 28a1524319 |
13 | 144098b431 |
14 | 97d797833 |
15 | 579bd49c3 |
hex | 349bccac5 |
14122011333 has 32 divisors (see below), whose sum is σ = 20180603520. Its totient is φ = 8753080320.
The previous prime is 14122011313. The next prime is 14122011347. The reversal of 14122011333 is 33311022141.
It is not a de Polignac number, because 14122011333 - 25 = 14122011301 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14122011313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1925313 + ... + 1932633.
It is an arithmetic number, because the mean of its divisors is an integer number (630643860).
Almost surely, 214122011333 is an apocalyptic number.
It is an amenable number.
14122011333 is a deficient number, since it is larger than the sum of its proper divisors (6058592187).
14122011333 is a wasteful number, since it uses less digits than its factorization.
14122011333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7797.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 14122011333 its reverse (33311022141), we get a palindrome (47433033474).
The spelling of 14122011333 in words is "fourteen billion, one hundred twenty-two million, eleven thousand, three hundred thirty-three".
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