Base | Representation |
---|---|
bin | 100000000111000100010111… |
… | …011101101101010010110100 |
3 | 200112000210210112220122220210 |
4 | 200013010113131231102310 |
5 | 122002300120102322234 |
6 | 1220205014253425420 |
7 | 41514016610010000 |
oct | 4007042735552264 |
9 | 615023715818823 |
10 | 141223213323444 |
11 | 40aa847926a86a |
12 | 13a0a00849b270 |
13 | 60a53a4328045 |
14 | 26c3350793700 |
15 | 114d8170c3be9 |
hex | 80711776d4b4 |
141223213323444 has 120 divisors (see below), whose sum is σ = 384481706575680. Its totient is φ = 40342812784512.
The previous prime is 141223213323371. The next prime is 141223213323461. The reversal of 141223213323444 is 444323312322141.
It is a super-2 number, since 2×1412232133234442 (a number of 29 digits) contains 22 as substring.
It is a nude number because it is divisible by every one of its digits.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 175033777 + ... + 175838759.
It is an arithmetic number, because the mean of its divisors is an integer number (3204014221464).
Almost surely, 2141223213323444 is an apocalyptic number.
141223213323444 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 141223213323444, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (192240853287840).
141223213323444 is an abundant number, since it is smaller than the sum of its proper divisors (243258493252236).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141223213323444 is an equidigital number, since it uses as much as digits as its factorization.
141223213323444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 811107 (or 811084 counting only the distinct ones).
The product of its digits is 331776, while the sum is 39.
Adding to 141223213323444 its reverse (444323312322141), we get a palindrome (585546525645585).
The spelling of 141223213323444 in words is "one hundred forty-one trillion, two hundred twenty-three billion, two hundred thirteen million, three hundred twenty-three thousand, four hundred forty-four".
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