Base | Representation |
---|---|
bin | 10100100011010000000… |
… | …111111011001010000011 |
3 | 12000000020111121121012220 |
4 | 110203100013323022003 |
5 | 141114232144330311 |
6 | 3000435150022123 |
7 | 204013435350513 |
oct | 24432007731203 |
9 | 5000214547186 |
10 | 1412241011331 |
11 | 4a4a23263287 |
12 | 1a98507a7943 |
13 | a3234984947 |
14 | 4c4d2243843 |
15 | 26b07b3b206 |
hex | 148d01fb283 |
1412241011331 has 8 divisors (see below), whose sum is σ = 1926778434240. Its totient is φ = 919598797992.
The previous prime is 1412241011317. The next prime is 1412241011351. The reversal of 1412241011331 is 1331101422141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1412241011331 - 210 = 1412241010307 is a prime.
It is a super-3 number, since 3×14122410113313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (1412241011351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5473802241 + ... + 5473802498.
It is an arithmetic number, because the mean of its divisors is an integer number (240847304280).
Almost surely, 21412241011331 is an apocalyptic number.
1412241011331 is a deficient number, since it is larger than the sum of its proper divisors (514537422909).
1412241011331 is a wasteful number, since it uses less digits than its factorization.
1412241011331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10947604785.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 1412241011331 its reverse (1331101422141), we get a palindrome (2743342433472).
The spelling of 1412241011331 in words is "one trillion, four hundred twelve billion, two hundred forty-one million, eleven thousand, three hundred thirty-one".
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