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14122433 = 1353103199
BaseRepresentation
bin110101110111…
…110111000001
3222120111100002
4311313313001
512103404213
61222405345
7231016163
oct65676701
928514302
1014122433
117a76436
124890855
132c06090
141c38933
15138e658
hexd77dc1

14122433 has 16 divisors (see below), whose sum is σ = 15724800. Its totient is φ = 12602304.

The previous prime is 14122429. The next prime is 14122463. The reversal of 14122433 is 33422141.

14122433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 14122433 - 22 = 14122429 is a prime.

It is a super-2 number, since 2×141224332 = 398886227678978, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14122403) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 70868 + ... + 71066.

It is an arithmetic number, because the mean of its divisors is an integer number (982800).

Almost surely, 214122433 is an apocalyptic number.

14122433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

14122433 is a deficient number, since it is larger than the sum of its proper divisors (1602367).

14122433 is a wasteful number, since it uses less digits than its factorization.

14122433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 368.

The product of its digits is 576, while the sum is 20.

The square root of 14122433 is about 3757.9825704758. The cubic root of 14122433 is about 241.7147619431.

Adding to 14122433 its reverse (33422141), we get a palindrome (47544574).

The spelling of 14122433 in words is "fourteen million, one hundred twenty-two thousand, four hundred thirty-three".

Divisors: 1 13 53 103 199 689 1339 2587 5459 10547 20497 70967 137111 266461 1086341 14122433