Base | Representation |
---|---|
bin | 1000001110000110101… |
… | …1110001000010100011 |
3 | 111111112020022120112112 |
4 | 2003201223301002203 |
5 | 4303212134101011 |
6 | 144513352145535 |
7 | 13126460146616 |
oct | 2034153610243 |
9 | 444466276475 |
10 | 141225300131 |
11 | 54991000283 |
12 | 234540982ab |
13 | 104186a4166 |
14 | 6b9a26617d |
15 | 3a185a858b |
hex | 20e1af10a3 |
141225300131 has 2 divisors, whose sum is σ = 141225300132. Its totient is φ = 141225300130.
The previous prime is 141225300077. The next prime is 141225300163. The reversal of 141225300131 is 131003522141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141225300131 - 230 = 140151558307 is a prime.
It is a super-2 number, since 2×1412253001312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 141225300097 and 141225300106.
It is not a weakly prime, because it can be changed into another prime (141225300031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70612650065 + 70612650066.
It is an arithmetic number, because the mean of its divisors is an integer number (70612650066).
Almost surely, 2141225300131 is an apocalyptic number.
141225300131 is a deficient number, since it is larger than the sum of its proper divisors (1).
141225300131 is an equidigital number, since it uses as much as digits as its factorization.
141225300131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 141225300131 its reverse (131003522141), we get a palindrome (272228822272).
The spelling of 141225300131 in words is "one hundred forty-one billion, two hundred twenty-five million, three hundred thousand, one hundred thirty-one".
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