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14123241553 is a prime number
BaseRepresentation
bin11010010011100111…
…11001000001010001
31100110021101000012111
431021303321001101
5212411022212203
610253234025321
71006662400231
oct151163710121
940407330174
1014123241553
115a98224463
1228a1a18241
131440ccc385
1497d9d7cc1
15579d7926d
hex349cf9051

14123241553 has 2 divisors, whose sum is σ = 14123241554. Its totient is φ = 14123241552.

The previous prime is 14123241533. The next prime is 14123241581. The reversal of 14123241553 is 35514232141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12522281409 + 1600960144 = 111903^2 + 40012^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14123241553 is a prime.

It is not a weakly prime, because it can be changed into another prime (14123241533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061620776 + 7061620777.

It is an arithmetic number, because the mean of its divisors is an integer number (7061620777).

Almost surely, 214123241553 is an apocalyptic number.

It is an amenable number.

14123241553 is a deficient number, since it is larger than the sum of its proper divisors (1).

14123241553 is an equidigital number, since it uses as much as digits as its factorization.

14123241553 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400, while the sum is 31.

Adding to 14123241553 its reverse (35514232141), we get a palindrome (49637473694).

The spelling of 14123241553 in words is "fourteen billion, one hundred twenty-three million, two hundred forty-one thousand, five hundred fifty-three".