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141232441222241 is a prime number
BaseRepresentation
bin100000000111001100111101…
…011111010110010001100001
3200112001200121122211111022022
4200013030331133112101201
5122002423014423102431
61220213142055351225
741514464360603015
oct4007147537262141
9615050548744268
10141232441222241
1141001384169806
1213a0b962982515
1360a62150800a5
1426c3988170545
15114dba72bb07b
hex80733d7d6461

141232441222241 has 2 divisors, whose sum is σ = 141232441222242. Its totient is φ = 141232441222240.

The previous prime is 141232441222217. The next prime is 141232441222247. The reversal of 141232441222241 is 142222144232141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123789322384225 + 17443118838016 = 11126065^2 + 4176496^2 .

It is a cyclic number.

It is not a de Polignac number, because 141232441222241 - 210 = 141232441221217 is a prime.

It is not a weakly prime, because it can be changed into another prime (141232441222247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70616220611120 + 70616220611121.

It is an arithmetic number, because the mean of its divisors is an integer number (70616220611121).

Almost surely, 2141232441222241 is an apocalyptic number.

It is an amenable number.

141232441222241 is a deficient number, since it is larger than the sum of its proper divisors (1).

141232441222241 is an equidigital number, since it uses as much as digits as its factorization.

141232441222241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 49152, while the sum is 35.

Adding to 141232441222241 its reverse (142222144232141), we get a palindrome (283454585454382).

The spelling of 141232441222241 in words is "one hundred forty-one trillion, two hundred thirty-two billion, four hundred forty-one million, two hundred twenty-two thousand, two hundred forty-one".