141233004445441 has 2 divisors, whose sum is σ = 141233004445442. Its totient is φ = 141233004445440.

The previous prime is 141233004445427. The next prime is 141233004445447. The reversal of 141233004445441 is 144544400332141.

141233004445441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113631336040000 + 27601668405441 = 10659800^2 + 5253729^2 .

It is a cyclic number.

It is not a de Polignac number, because 141233004445441 - 2³¹ = 141230856961793 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141233004445394 and 141233004445403.

It is not a weakly prime, because it can be changed into another prime (141233004445447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70616502222720 + 70616502222721.

It is an arithmetic number, because the mean of its divisors is an integer number (70616502222721).

Almost surely, 2^{141233004445441} is an apocalyptic number.

It is an amenable number.

141233004445441 is a deficient number, since it is larger than the sum of its proper divisors (1).

141233004445441 is an equidigital number, since it uses as much as digits as its factorization.

141233004445441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 368640, while the sum is 40.

Adding to 141233004445441 its reverse (144544400332141), we get a palindrome (285777404777582).

The spelling of 141233004445441 in words is "one hundred forty-one trillion, two hundred thirty-three billion, four million, four hundred forty-five thousand, four hundred forty-one".