14124012343 has 4 divisors (see below), whose sum is σ = 16141728400. Its totient is φ = 12106296288.

The previous prime is 14124012341. The next prime is 14124012377. The reversal of 14124012343 is 34321042141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34321042141 = 19 ⋅1806370639.

It is a cyclic number.

It is not a de Polignac number, because 14124012343 - 2¹ = 14124012341 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14124012341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1008858018 + ... + 1008858031.

It is an arithmetic number, because the mean of its divisors is an integer number (4035432100).

Almost surely, 2^14124012343 is an apocalyptic number.

14124012343 is a deficient number, since it is larger than the sum of its proper divisors (2017716057).

14124012343 is an equidigital number, since it uses as much as digits as its factorization.

14124012343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2017716056.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14124012343 its reverse (34321042141), we get a palindrome (48445054484).

The spelling of 14124012343 in words is "fourteen billion, one hundred twenty-four million, twelve thousand, three hundred forty-three".