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141242420231401 is a prime number
BaseRepresentation
bin100000000111010110010000…
…010010001111110011101001
3200112002122101010002200102011
4200013112100102033303221
5122003103434034401101
61220221512212235521
741515266562021126
oct4007262022176351
9615078333080364
10141242420231401
1141005635047015
1213a1188890bba1
1360a71455cb138
1426c42535cb74d
15114e08d3ce751
hex80759048fce9

141242420231401 has 2 divisors, whose sum is σ = 141242420231402. Its totient is φ = 141242420231400.

The previous prime is 141242420231303. The next prime is 141242420231431. The reversal of 141242420231401 is 104132024242141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120329908311001 + 20912511920400 = 10969499^2 + 4573020^2 .

It is a cyclic number.

It is not a de Polignac number, because 141242420231401 - 29 = 141242420230889 is a prime.

It is not a weakly prime, because it can be changed into another prime (141242420231431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70621210115700 + 70621210115701.

It is an arithmetic number, because the mean of its divisors is an integer number (70621210115701).

Almost surely, 2141242420231401 is an apocalyptic number.

It is an amenable number.

141242420231401 is a deficient number, since it is larger than the sum of its proper divisors (1).

141242420231401 is an equidigital number, since it uses as much as digits as its factorization.

141242420231401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 141242420231401 its reverse (104132024242141), we get a palindrome (245374444473542).

The spelling of 141242420231401 in words is "one hundred forty-one trillion, two hundred forty-two billion, four hundred twenty million, two hundred thirty-one thousand, four hundred one".