Base | Representation |
---|---|
bin | 100000000111010110010000… |
… | …010010001111111100100011 |
3 | 200112002122101010002201012021 |
4 | 200013112100102033330203 |
5 | 122003103434034410341 |
6 | 1220221512212242311 |
7 | 41515266562022602 |
oct | 4007262022177443 |
9 | 615078333081167 |
10 | 141242420231971 |
11 | 41005635047493 |
12 | 13a11888910397 |
13 | 60a71455cb486 |
14 | 26c42535cba39 |
15 | 114e08d3ce9d1 |
hex | 80759048ff23 |
141242420231971 has 2 divisors, whose sum is σ = 141242420231972. Its totient is φ = 141242420231970.
The previous prime is 141242420231963. The next prime is 141242420232013. The reversal of 141242420231971 is 179132024242141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141242420231971 - 23 = 141242420231963 is a prime.
It is not a weakly prime, because it can be changed into another prime (141242420231921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70621210115985 + 70621210115986.
It is an arithmetic number, because the mean of its divisors is an integer number (70621210115986).
Almost surely, 2141242420231971 is an apocalyptic number.
141242420231971 is a deficient number, since it is larger than the sum of its proper divisors (1).
141242420231971 is an equidigital number, since it uses as much as digits as its factorization.
141242420231971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 193536, while the sum is 43.
The spelling of 141242420231971 in words is "one hundred forty-one trillion, two hundred forty-two billion, four hundred twenty million, two hundred thirty-one thousand, nine hundred seventy-one".
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