Base | Representation |
---|---|
bin | 11010010011110000… |
… | …00111111000010001 |
3 | 1100110100110101001212 |
4 | 31021320013320101 |
5 | 212411313212433 |
6 | 10253313505505 |
7 | 1010005000604 |
oct | 151170077021 |
9 | 40410411055 |
10 | 14124350993 |
11 | 5a98911a55 |
12 | 28a2272295 |
13 | 14412ca34c |
14 | 97dc0633b |
15 | 579ee7d48 |
hex | 349e07e11 |
14124350993 has 2 divisors, whose sum is σ = 14124350994. Its totient is φ = 14124350992.
The previous prime is 14124350971. The next prime is 14124351013. The reversal of 14124350993 is 39905342141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8837316049 + 5287034944 = 94007^2 + 72712^2 .
It is a cyclic number.
It is not a de Polignac number, because 14124350993 - 210 = 14124349969 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14124350993.
It is not a weakly prime, because it can be changed into another prime (14124350893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062175496 + 7062175497.
It is an arithmetic number, because the mean of its divisors is an integer number (7062175497).
Almost surely, 214124350993 is an apocalyptic number.
It is an amenable number.
14124350993 is a deficient number, since it is larger than the sum of its proper divisors (1).
14124350993 is an equidigital number, since it uses as much as digits as its factorization.
14124350993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 41.
The spelling of 14124350993 in words is "fourteen billion, one hundred twenty-four million, three hundred fifty thousand, nine hundred ninety-three".
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