Base | Representation |
---|---|
bin | 1100110110001001101001… |
… | …1011011001000101011011 |
3 | 1212000021122202000200102121 |
4 | 3031202122123121011123 |
5 | 3322403324443404042 |
6 | 50012402451442111 |
7 | 2655312605323246 |
oct | 315423233310533 |
9 | 55007582020377 |
10 | 14124443341147 |
11 | 4556163051777 |
12 | 17014b35b6337 |
13 | 7b5c10867859 |
14 | 36b8ab97225d |
15 | 197620eee367 |
hex | cd89a6d915b |
14124443341147 has 2 divisors, whose sum is σ = 14124443341148. Its totient is φ = 14124443341146.
The previous prime is 14124443341087. The next prime is 14124443341163. The reversal of 14124443341147 is 74114334442141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14124443341147 is a prime.
It is not a weakly prime, because it can be changed into another prime (14124443344147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062221670573 + 7062221670574.
It is an arithmetic number, because the mean of its divisors is an integer number (7062221670574).
Almost surely, 214124443341147 is an apocalyptic number.
14124443341147 is a deficient number, since it is larger than the sum of its proper divisors (1).
14124443341147 is an equidigital number, since it uses as much as digits as its factorization.
14124443341147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 516096, while the sum is 43.
Adding to 14124443341147 its reverse (74114334442141), we get a palindrome (88238777783288).
The spelling of 14124443341147 in words is "fourteen trillion, one hundred twenty-four billion, four hundred forty-three million, three hundred forty-one thousand, one hundred forty-seven".
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