Base | Representation |
---|---|
bin | 1000001110001100001… |
… | …0110001111011101001 |
3 | 111111120211020110020002 |
4 | 2003203002301323221 |
5 | 4303234004012223 |
6 | 144515525112345 |
7 | 13130155061612 |
oct | 2034302617351 |
9 | 444524213202 |
10 | 141248110313 |
11 | 549a296a972 |
12 | 2345b8586b5 |
13 | 1042032c6cb |
14 | 6b9d2c2c09 |
15 | 3a1a5b1e28 |
hex | 20e30b1ee9 |
141248110313 has 2 divisors, whose sum is σ = 141248110314. Its totient is φ = 141248110312.
The previous prime is 141248110303. The next prime is 141248110319. The reversal of 141248110313 is 313011842141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 135215792089 + 6032318224 = 367717^2 + 77668^2 .
It is a cyclic number.
It is not a de Polignac number, because 141248110313 - 212 = 141248106217 is a prime.
It is not a weakly prime, because it can be changed into another prime (141248110319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70624055156 + 70624055157.
It is an arithmetic number, because the mean of its divisors is an integer number (70624055157).
Almost surely, 2141248110313 is an apocalyptic number.
It is an amenable number.
141248110313 is a deficient number, since it is larger than the sum of its proper divisors (1).
141248110313 is an equidigital number, since it uses as much as digits as its factorization.
141248110313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 29.
Adding to 141248110313 its reverse (313011842141), we get a palindrome (454259952454).
The spelling of 141248110313 in words is "one hundred forty-one billion, two hundred forty-eight million, one hundred ten thousand, three hundred thirteen".
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