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141248110313 is a prime number
BaseRepresentation
bin1000001110001100001…
…0110001111011101001
3111111120211020110020002
42003203002301323221
54303234004012223
6144515525112345
713130155061612
oct2034302617351
9444524213202
10141248110313
11549a296a972
122345b8586b5
131042032c6cb
146b9d2c2c09
153a1a5b1e28
hex20e30b1ee9

141248110313 has 2 divisors, whose sum is σ = 141248110314. Its totient is φ = 141248110312.

The previous prime is 141248110303. The next prime is 141248110319. The reversal of 141248110313 is 313011842141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 135215792089 + 6032318224 = 367717^2 + 77668^2 .

It is a cyclic number.

It is not a de Polignac number, because 141248110313 - 212 = 141248106217 is a prime.

It is not a weakly prime, because it can be changed into another prime (141248110319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70624055156 + 70624055157.

It is an arithmetic number, because the mean of its divisors is an integer number (70624055157).

Almost surely, 2141248110313 is an apocalyptic number.

It is an amenable number.

141248110313 is a deficient number, since it is larger than the sum of its proper divisors (1).

141248110313 is an equidigital number, since it uses as much as digits as its factorization.

141248110313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 141248110313 its reverse (313011842141), we get a palindrome (454259952454).

The spelling of 141248110313 in words is "one hundred forty-one billion, two hundred forty-eight million, one hundred ten thousand, three hundred thirteen".