Base | Representation |
---|---|
bin | 1100110110001011101110… |
… | …1100010001001101001111 |
3 | 1212000100002122010200201100 |
4 | 3031202323230101031033 |
5 | 3322411000330212310 |
6 | 50012534105114143 |
7 | 2655332463005232 |
oct | 315427354211517 |
9 | 55010078120640 |
10 | 14125001413455 |
11 | 455641a072759 |
12 | 170162a488953 |
13 | 7b5c9c37335a |
14 | 36b921b23419 |
15 | 197654ed8ec0 |
hex | cd8bbb1134f |
14125001413455 has 48 divisors (see below), whose sum is σ = 24531589368000. Its totient is φ = 7518494075904.
The previous prime is 14125001413447. The next prime is 14125001413487. The reversal of 14125001413455 is 55431410052141.
14125001413455 is a `hidden beast` number, since 1 + 4 + 1 + 2 + 500 + 14 + 134 + 5 + 5 = 666.
It is not a de Polignac number, because 14125001413455 - 23 = 14125001413447 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 96179421 + ... + 96326169.
It is an arithmetic number, because the mean of its divisors is an integer number (511074778500).
Almost surely, 214125001413455 is an apocalyptic number.
14125001413455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14125001413455 is a deficient number, since it is larger than the sum of its proper divisors (10406587954545).
14125001413455 is a wasteful number, since it uses less digits than its factorization.
14125001413455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 150960 (or 150957 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 36.
Adding to 14125001413455 its reverse (55431410052141), we get a palindrome (69556411465596).
The spelling of 14125001413455 in words is "fourteen trillion, one hundred twenty-five billion, one million, four hundred thirteen thousand, four hundred fifty-five".
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