Base | Representation |
---|---|
bin | 1100110110001011101111… |
… | …0110010010110011010001 |
3 | 1212000100002211002012121120 |
4 | 3031202323312102303101 |
5 | 3322411002013311200 |
6 | 50012534241312453 |
7 | 2655332524232034 |
oct | 315427366226321 |
9 | 55010084065546 |
10 | 14125004041425 |
11 | 45564205a8132 |
12 | 170162b335729 |
13 | 7b5c9ca83574 |
14 | 36b92220901b |
15 | 1976553579a0 |
hex | cd8bbd92cd1 |
14125004041425 has 24 divisors (see below), whose sum is σ = 23363165021856. Its totient is φ = 7530166131840.
The previous prime is 14125004041411. The next prime is 14125004041427. The reversal of 14125004041425 is 52414040052141.
It is not a de Polignac number, because 14125004041425 - 24 = 14125004041409 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (14125004041427) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 39437499 + ... + 39794048.
It is an arithmetic number, because the mean of its divisors is an integer number (973465209244).
Almost surely, 214125004041425 is an apocalyptic number.
14125004041425 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14125004041425 is a deficient number, since it is larger than the sum of its proper divisors (9238160980431).
14125004041425 is a wasteful number, since it uses less digits than its factorization.
14125004041425 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79233937 (or 79233932 counting only the distinct ones).
The product of its (nonzero) digits is 25600, while the sum is 33.
Adding to 14125004041425 its reverse (52414040052141), we get a palindrome (66539044093566).
The spelling of 14125004041425 in words is "fourteen trillion, one hundred twenty-five billion, four million, forty-one thousand, four hundred twenty-five".
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