Base | Representation |
---|---|
bin | 1100110110001011110111… |
… | …1111011110001000010011 |
3 | 1212000100012022202011122020 |
4 | 3031202331333132020103 |
5 | 3322411040220022210 |
6 | 50012542004142523 |
7 | 2655333442003050 |
oct | 315427577361023 |
9 | 55010168664566 |
10 | 14125040001555 |
11 | 455643992954a |
12 | 170163b397a43 |
13 | 7b5ca7364352 |
14 | 36b926cca027 |
15 | 1976585ac770 |
hex | cd8bdfde213 |
14125040001555 has 64 divisors (see below), whose sum is σ = 25881052102656. Its totient is φ = 6444068400000.
The previous prime is 14125040001551. The next prime is 14125040001559. The reversal of 14125040001555 is 55510004052141.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (14125040001551) and next prime (14125040001559).
It is not a de Polignac number, because 14125040001555 - 22 = 14125040001551 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14125040001551) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 153069180 + ... + 153161430.
It is an arithmetic number, because the mean of its divisors is an integer number (404391439104).
Almost surely, 214125040001555 is an apocalyptic number.
14125040001555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14125040001555 is a deficient number, since it is larger than the sum of its proper divisors (11756012101101).
14125040001555 is a wasteful number, since it uses less digits than its factorization.
14125040001555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95208.
The product of its (nonzero) digits is 20000, while the sum is 33.
Adding to 14125040001555 its reverse (55510004052141), we get a palindrome (69635044053696).
The spelling of 14125040001555 in words is "fourteen trillion, one hundred twenty-five billion, forty million, one thousand, five hundred fifty-five".
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