Base | Representation |
---|---|
bin | 101010000110001… |
… | …1010100000111001 |
3 | 10122102221111020211 |
4 | 1110030122200321 |
5 | 10343102243343 |
6 | 352055351121 |
7 | 50001252541 |
oct | 12414324071 |
9 | 3572844224 |
10 | 1412540473 |
11 | 665384623 |
12 | 3350824a1 |
13 | 19684c786 |
14 | d5858321 |
15 | 8402079d |
hex | 5431a839 |
1412540473 has 2 divisors, whose sum is σ = 1412540474. Its totient is φ = 1412540472.
The previous prime is 1412540399. The next prime is 1412540501. The reversal of 1412540473 is 3740452141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 975437824 + 437102649 = 31232^2 + 20907^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1412540473 is a prime.
It is not a weakly prime, because it can be changed into another prime (1412540573) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706270236 + 706270237.
It is an arithmetic number, because the mean of its divisors is an integer number (706270237).
Almost surely, 21412540473 is an apocalyptic number.
It is an amenable number.
1412540473 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412540473 is an equidigital number, since it uses as much as digits as its factorization.
1412540473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 31.
The square root of 1412540473 is about 37583.7793868578. The cubic root of 1412540473 is about 1122.0192296657.
The spelling of 1412540473 in words is "one billion, four hundred twelve million, five hundred forty thousand, four hundred seventy-three".
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