14125532345201 has 4 divisors (see below), whose sum is σ = 14196514920000. Its totient is φ = 14054549770404.

The previous prime is 14125532345153. The next prime is 14125532345203. The reversal of 14125532345201 is 10254323552141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14125532345201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14125532345203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35491287101 + ... + 35491287498.

It is an arithmetic number, because the mean of its divisors is an integer number (3549128730000).

Almost surely, 2^{14125532345201} is an apocalyptic number.

It is an amenable number.

14125532345201 is a deficient number, since it is larger than the sum of its proper divisors (70982574799).

14125532345201 is an equidigital number, since it uses as much as digits as its factorization.

14125532345201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70982574798.

The product of its (nonzero) digits is 144000, while the sum is 38.

Adding to 14125532345201 its reverse (10254323552141), we get a palindrome (24379855897342).

The spelling of 14125532345201 in words is "fourteen trillion, one hundred twenty-five billion, five hundred thirty-two million, three hundred forty-five thousand, two hundred one".