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14128011207 = 323194153813
BaseRepresentation
bin11010010100001100…
…00101011111000111
31100110121100022221100
431022012011133013
5212413232324312
610253524151143
71010051054022
oct151206053707
940417308840
1014128011207
115a9a991a22
1228a35384b3
131441cac35b
149804ba1b9
1557a4bc5dc
hex34a1857c7

14128011207 has 24 divisors (see below), whose sum is σ = 21088199808. Its totient is φ = 9104990400.

The previous prime is 14128011179. The next prime is 14128011239. The reversal of 14128011207 is 70211082141.

14128011207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 14128011207 - 28 = 14128010951 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14128011307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 235633 + ... + 289445.

It is an arithmetic number, because the mean of its divisors is an integer number (878674992).

Almost surely, 214128011207 is an apocalyptic number.

14128011207 is a deficient number, since it is larger than the sum of its proper divisors (6960188601).

14128011207 is a wasteful number, since it uses less digits than its factorization.

14128011207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54791 (or 54788 counting only the distinct ones).

The product of its (nonzero) digits is 896, while the sum is 27.

Adding to 14128011207 its reverse (70211082141), we get a palindrome (84339093348).

The spelling of 14128011207 in words is "fourteen billion, one hundred twenty-eight million, eleven thousand, two hundred seven".

Divisors: 1 3 9 31 93 279 941 2823 8469 29171 53813 87513 161439 262539 484317 1668203 5004609 15013827 50638033 151914099 455742297 1569779023 4709337069 14128011207